00:01
We have been given the value of cosec theta as 1 .5.
00:06
So with the help of this we can find that sine theta is 1 upon cosec theta, right? so it is nothing but you can see 1 divided by 1 .5 which is nothing but 10 divided by 15.
00:23
Right.
00:24
So further reducing it, we get here 2 by 3.
00:27
Now we know this notation that for finding the trigonometric ratio we have this particular thing, right? so this one, first one, second one and third one are sine, cos and 10 respectively p, b and h are perpendicular base and hypotenous.
00:44
So first go and let us draw this particular right angle triangle with your angle as theta.
00:50
Right.
00:51
Now what we have is according to sine theta, it's nothing but perpendicular by hypotenus.
00:56
So perpendicular is your suppose 2 and 2 multiplied by k because here we are taking ratio so we have to take a constant right.
01:03
So 2k and your hypotenus is nothing but 3k you can write right so you need to find this particular value of x that is base.
01:12
So according to pythogorostrum we get 3k square is equals to 2k square plus x square so it gives you x square is nothing but 5k square okay.
01:26
X becomes root 5k...