Question
Given: $A$ is equidistant from B and D (that is, $A B=A D$ ). $\overrightarrow{\mathrm{AC}}$ bisects $\angle \mathrm{BAD}$Prove: $\angle \mathrm{MQP} \cong \angle \mathrm{SQP}$(FIGURE CAN NOT BE COPY)
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Step 1: Given that $AB = AD$ and $\overrightarrow{AC}$ bisects $\angle BAD$. Show more…
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