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Given:$\begin{array}{ll}{\mathrm{P}_{4}(s)+5 \mathrm{O}_{2}(g) \longrightarrow \mathrm{P}_{4} \mathrm{O}_{10}(s)} & {\Delta G_{298}^{\circ}=-2697.0 \mathrm{kJ} / \mathrm{mol}} \\ {2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)} & {\Delta G_{298}^{\circ}=-457.18 \mathrm{kJ} / \mathrm{mol}} \\ {6 \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{P}_{4} \mathrm{O}_{10}(s) \longrightarrow 4 \mathrm{H}_{3} \mathrm{PO}_{4}(l)} & {\Delta G_{298}^{\circ}=-428.66 \mathrm{kJ} / \mathrm{mol}}\end{array}$(a) Determine the standard free energy of formation, $\Delta G_{\mathrm{f}}^{\circ}$ , for phosphoric acid.(b) How does your calculated result compare to the value in Appendix G? Explain.
$G_{f}\left(H_{3} P O_{4}, l\right)=-1124.3 \frac{k J}{m o l}$
Chemistry 102
Chapter 16
Thermodynamics
University of Central Florida
University of Maryland - University College
University of Kentucky
Brown University
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there are two laws for this question. The standard free energy off formation means change in free energy, accompanying the formation off one more off substance from its element in Standard State. It is donated US Delta Ji, as shown on their second local elders, Heslop. It states that weather reaction take place in one step or several steps. The Intel B change always remain the same. So for auctioning, considering the reaction this value off standard and tell you or formation at room temperature can be calculated by using the head slow as shown by question. 1213 at the first reaction with three times the second reaction, and then also add the third reaction after canceling out the dome's No, we have the standard equation for above reaction that is, Delta G will be equals negative off 4497 points. Tokelo Jules, Dividing the equation by four To get the equation for Delta G equals minus 1124.3 jewels. Hello, Jules. We have standard free energy for formation over here on for Option B. The free energy is the state function on its Jane's depends upon the initial and final state, not on the part between them. The calculation off standard free energy change remains the same as the value in appendix G.
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