Question
Given $f(x)=2 x^{3}-14 x^{2}+b x-3$ with $f(2)=0, g(x)=x^{3}+c x^{2}-8 x+30$, with the zero $x=3-i,$ and $b$ and $c$ real numbers, find $(f \cdot g)(1)$.
Step 1
We can use this information to find the value of $b$. Substituting $x=2$ into the equation for $f(x)$, we get: $$f(2)=2(2)^3-14(2)^2+b(2)-3=0$$ Solving this equation for $b$ gives us: $$b=\frac{56-16+3}{2}=21.5$$ Show more…
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