This relationship is given by the following equation:
$$I_D = I_{DSS} \left(1 - \frac{V_{GS}}{V_P}\right)^2$$
Now, we can use this equation to find the drain current $I_D$ for each given gate-source voltage $V_{GS}$.
a. $V_{GS} = 0 \mathrm{~V}$:
$$I_D = 9
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