00:01
So we're given the probability of a sub 1 is equal to 0 .6.
00:06
The probability of the conditional of b1, given that a1 already took place, is 0 .6.
00:12
And the probability of b1 given a sub 2 is equal to 0 .4.
00:19
And we want to find the probability of a1 given b1.
00:26
And so we're going to draw our little chart.
00:30
I don't know what formulas you're given, and i'm just going to start doing it the way i do it.
00:37
And a1 and a2 are going to be complements, and b1 and b2 are going to be complements.
00:43
And so we know that the probability that a happens is this value here, which means the probability of a sub 2 happens is 0 .4, and these two add up to 1.
00:56
Now, the other values we don't know, and these are all intersections here, a1 and b1, a2 and b1, etc.
01:04
So let's use, first of all, this little given information here and fill in some more information.
01:11
So we know that this conditional means the probability of b1 and a1 divided by the probability of a1.
01:22
However, we know that a1, and this, by the way, is equal to 0 .6.
01:28
We know that the probability of a sub 1 is 0 .6, so we can do a substitution.
01:33
And then we can find the probability of that intersection, which is this value in our chart, by taking 0 .6 times 0 .6, and that is 0 .36.
01:42
Therefore, this value will have to be 0 .24.
01:45
These have to add up to 0 .6.
01:47
So now we can go to this information and do a similar analysis.
01:53
We know that this value comes from b1 and a sub 2 divided by the probability of a sub 2...