Question
Given that $f$ and $g$ are continuous on $[a, b],$ that $f(a)$ $g(a),$ and $g(b)<f(b),$ show that there exists at least one number $c$ in $(a, b)$ such that $f(c)=g(c)$. HINT: Consider $f(x)-g(x).$
Step 1
Since $f$ and $g$ are continuous on $[a, b]$, their difference $h$ is also continuous on $[a, b]$. Show more…
Show all steps
Your feedback will help us improve your experience
Nick Johnson and 95 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Given that $f$ and $g$ are continuous on $[a, b],$ that $f(a)<$ $g(a),$ and $g(b)<f(b),$ show that there exists at Icast one number $c$ in $(a, b)$ such that $f(c)=g(c) .$ HINT: Consider $f(x)-g(x)$
Limits and Continuity
Two Basic Theorems
Given that $f$ and $g$ are continuous on $[a, b]$ such that $f(a)>g(a)$ and $f(b)<g(b),$ show that there is a number $c$ in $(a, b)$ such that $f(c)=g(c) .$ [Hint: Consider the function $f-g .]$
Limit of a Function
Continuity
Prove: If $f$ and $g$ are continuous on $[a, b],$ and $f(a)>g(a)$ $f(b)<g(b),$ then there is at least one solution of the equation $f(x)=g(x) \text { in }(a, b) . \text { [Hint: Consider } f(x)-g(x) .]$
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD