00:01
Suppose we're given that wave functions psi 1 and psi 2 are solutions to the schrodinger equation copied here.
00:11
We want to show that if this is the case, then some linear combination of these solutions, also there are solutions with the same energy e.
00:23
Then we want to show that this linear combination of those wave functions with arbitrary constants a and b is also a solution, also with energy e.
00:32
And so what we'll do is we'll start by plugging in.
00:37
What we'll do is we'll show that if we use this new wave function, on the left side of the equation, we will get the right side of the equation with the same energy.
00:46
So we'll go ahead and start.
00:48
We know that this is true for psi 1 and side 2, d x squared.
00:55
And so for psi, we're plugging in our linear combination of these solutions.
01:01
Then we've got u.
01:02
We might write u of x.
01:05
Then here's our equation.
01:10
Okay.
01:12
So we want to show that this is equal to e, a, psi 1 plus b, side 2.
01:18
And so to do that, we're going to rearrange this and use the fact that psi 1 and psi 2 are both solutions.
01:27
And so we'll go ahead and rearrange this and group the psi 1 terms and group the si 2 terms.
01:34
So h bar squared over 2m d squared d x squared of a a...