Question
Given that the graph of $f$ passes through the point $(2,5)$ and that the slope of its tangent line at $(x, f(x))$ is $3-4 x$, find $f(1)$.
Step 1
The antiderivative of a constant is the constant times $x$, and the antiderivative of $x$ is $\frac{1}{2}x^2$. So, the antiderivative of $f'(x)$ is $f(x) = 3x - 2x^2 + C$, where $C$ is the constant of integration. Show more…
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