Given the following electrode potentials at $25^{\circ} \mathrm{C}$
\[
\begin{aligned}
\mathrm{Fe}^{3+}+\mathrm{e}^{-} &=\mathrm{Fe}^{2+} & & E_{1}^{\circ}=0.771 \mathrm{V} \\
\frac{1}{2} \mathrm{Fe}^{2+}+\mathrm{e}^{-} &=\frac{1}{2} \mathrm{Fe}(\mathrm{s}) & E_{2}^{\circ} &=-0.440 \mathrm{V}
\end{aligned}
\]
calculate the electrode potential for
\[
\frac{1}{3} \mathrm{Fe}^{3+}+\mathrm{e}^{-}=\frac{1}{3} \mathrm{Fe} \quad E_{3}^{\circ}=?
\]