00:01
So given the following standard reduction potentials, we are asked to find the kf for ag cn2 minus at 25 degrees celsius.
00:09
And we're going to go ahead and use the fact that delta g is equal to negative rtln of k and that it's also equal to negative nfe cell.
00:19
And we're going to set those two equal to each other.
00:22
So the thing that we really want to find first is this e because everything else is pretty much a constant, and of course, we're solving for k.
00:32
So here, e is equal to e reduced minus e oxidized.
00:37
So we're looking at the reduction potential for the reduction and the oxidation reactions.
00:43
And the way that we figure that out is we know that we want to get ag, cn2 minus formed.
00:50
So here, it's actually found right over in the second equation, but you can see that it's actually not being formed.
00:58
So what we have to really look at is we want to go this way.
01:02
We want to go to the left...