Question
Given the general term of each sequence, find each of the following.$a_{n}=\frac{3 n-1}{4 n+5}$a) $a$ ab) $a_{10}$c) the 21 st term
Step 1
To find the first term, we substitute $n=1$ into the equation. So, $a_{1}=\frac{3(1)-1}{4(1)+5}=\frac{2}{9}$. Show more…
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