According to Fig. 123, the current $I_{C}$ is 2 mA and the voltage across the collector resistor $V_{C}$ is 6 V. Using Ohm's law, we can find $R_{C}$:
$R_{C} = \frac{V_{C}}{I_{C}} = \frac{6V}{2mA} = 3k\Omega$
b. Similarly, to find $R_{E}$, we need to know the
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