Question
Given the random variable $X$ with probability distribution $$f(x)=\left\{\begin{array}{ll}2 x, & 0<x<1 \\ 0, & \text {}\end{array}\right.$$ find the probability distribution of $Y=8 X^{3}$.
Step 1
This is given by $X=(Y/8)^{1/3}$, which is valid for $0<Y<8$. Show more…
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