00:01
We're asked to use structural induction show that l of t, which is the number of leaves on a full binary tree, t is one more than i of t, which is the number of internal vertices of the tree t.
00:55
So for the basis step, we have that the height of the tree, t, is zero, so that the tree only contains a root, call it r.
01:36
The root is a leaf, but not an internal vertex.
01:42
So it follows that number of leaves of t is one, and the number of internal vertices of t is zero.
01:51
And so we have that, in this case, leaves of t, which is 1, equals 1 plus 0, which is equal to i of t plus 1...