00:01
In this problem we have been given, z is equal to cost 2 pi by 13 plus iota sign 2 pi by 13 and the equation whose roots are alpha and beta where alpha is equal to 1 plus z plus z plus z to the power of 5 plus z to the power of 7 plus z to the power of 9 plus z to the power of 11 and beta is equal to 1 plus z squared plus z to the power of 4 plus z to the power of 6 plus z to the power of 8 plus z to the power of 10 plus z to the power of 12 is a.
00:26
So we have been given to ask.
00:30
So we have been given four options.
00:32
So now let us proceed with the question.
00:34
Now we have been given that z is equal to cos 2 pi by 13 plus iota sign 2 pi by 13 so therefore z to the power of 13 would be equal to 1 so now therefore that would be equal now alpha would be equal to 1 plus z plus z to the power of 3 plus z to the power of 5 plus z to the power of 7 plus z to the power of 9 plus z to the power of 11 as given so therefore this would be equal to 1 plus z into 1 minus z to the power of 12, 4 divided by 1 minus z square.
01:48
All right, so this would be equal to 1 plus z minus z to the power of 13, all divided by 1 minus z square.
02:05
So this would be equal to 1 plus z minus 1, 2, 0 minus z square so therefore now since z to the power of 13 equal to 1 as it is the 13 cube root of unity so therefore that implies this would be equal to 1 plus now z minus 1 1 divided by 1 minus x squared so 1 plus minus 1 divided by 1 plus z so this would be equal to z upon 1 plus z all right so beta would be equal to from the expression 1 plus z square plus z to the power of 4 plus z to the power of 6 plus z to the power of 8 plus z to the power of 10 plus z to the power of 12 now this would be equal to 1 into 1 1 minus z to the power of 14 whole divided by 1 minus z square.
03:27
This is z square.
03:29
Alright, so therefore this would be equal to 1 upon 1 plus z.
03:37
Now, so alpha, therefore alpha plus beta would be equal to 1...