00:01
So this question belongs to the fluid mechanics in which we have glycerine which is flowing steadily through horizontal tube of length l equals to 1 .5 meter and radius of the tube small r it is equal to 1 cm that is equal to 10 to the power minus 2 meter.
00:16
And if the amount of the glycerine collected per second at the one end it is equals to that is flow rate so we can take it a small m this is equal to or we can take it m dot so so this is equal to 4 .0 multiplied by 10 to the power minus 3, clogram per second, and we have to determine the pressure difference between the end of the tube.
00:41
So now we can write that density of the glycerine, row, it is equal to 1 .3 modplied weight 10 to the power 3, clogram per meter cube, and viscosity of the glycerine, eta, it is equals to 0 .83 pascal second.
00:58
Okay, so we can calculate that volume of the, first of all, volume of the glycerine flowing per second, that is v.
01:05
Dot, it will be equals to mass flow rate divided by density row.
01:09
So it is equal to 4 .0 multiplier b 10 to the power minus 3 divided by density, which is 1 .3 modiplier by 10 to the power 3 .08 multiply by 10 to the power minus 6 meter cube per second.
01:24
Okay.
01:25
Now, according to the poysel formula, we can write that.
01:28
Volume flow rate v.
01:29
This is equal to pi pressure p, multiplied by r to the power 4, divided by 8, eta, l...