00:01
For this problem on the topic of electric circuits, we have a water heater that holds 52 gallons and starts with cold water at 11 degrees celsius and delivers hot water at 53 degrees celsius.
00:12
The unit is electric and uses a resistance heater, which is 112 .20 volt ac with the resistance of 3 oms in order to heat the water.
00:22
Now we want to calculate the time that is required to heat all of the water to the temperature of 53 degrees celsius.
00:30
So for this problem, the higher the average power output of the resistance heater, the faster it can supply the heat energy q needed to raise the water temperature.
00:41
And this follows from p equal to q over t, which implies that the recovery time, t is q over p.
00:52
The average power output of the resistance heater is p, and this is given by the rms voltage squared over the resistance of the resistor and this is the resistance of the heater in this case and the rms voltage is 120 volts.
01:10
The heater must supply an amount of heat energy q which is cm times delta t to cause an increase of delta t in the temperature of a mass m of water where the specific heat capacity of water is 4 ,186 joules per kg degrees celsius.
01:29
The mass m of the water can be found from density, row is 1 ,000 kilograms per cubic meter and the volume of water that is held in the heater according to m is equal to row times v...