Question
Grading One professor grades homework by randomly choosing 5 out of 12 homework problems to grade.(a) How many different groups of 5 problems can be chosen from the 12 problems?(b) Probability Extension Jerry did only 5 problems of one assignment. What is the probability that the problems he did comprised the group that was selected to be graded?(c) Silvia did 7 problems. How many different groups of 5 did she complete? What is the probability that one of the groups of 5 she completed comprised the group selected to be graded?
Step 1
So, for this problem, \( n = 12 \) and \( k = 5 \). Substituting these values into the formula, we get: \[ C(12, 5) = \frac{12!}{5!(12-5)!} = 792 \] Show more…
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