00:01
So for this problem, we want to try to get this into a standard form to see what we're dealing with, and then write the domain and range.
00:10
So what i'm going to do first here is square both sides to get rid of that square root.
00:20
So that would give me y squared over four equals.
00:26
So the square root is going to cancel 1 minus x squared over 25.
00:35
So then i'm going to add the x squared over 25 to the other side and graph this ellipse, because what we did get is an ellipse.
00:56
So we know here that the center is zero, because my h and k are not, you don't see an h or k value in there because you just have an x and a y.
01:09
So here's zero, zero.
01:13
And my a value is going to be the square root of the bigger number.
01:17
So a squared equals 25, which means a is 5...