00:01
Hey guys, in this problem we're going to be graphing the function g of x equals negative e to the one half x power and also finding the critical data points.
00:09
So first off let's go ahead and get some data points at x equals negative 1 the function will be negative e to the negative one half power.
00:17
Let's put that in our calculator it's going to be negative 0 .607 at x equals 0 this whole term will become 1 negative so negative 1 at x equals 1 we have one half times 1 that's negative e to the negative e to the 1 half power and that should be negative 1 .65 at x equals 2 this should become 1 negative e to the first power that should just be negative 2 .7 2 so let's go ahead and graph at x equals negative 1.
01:21
We had negative 6 .607.
01:26
Then we had negative 1, negative 1 .65, and let's see 1, 2, closer to 3.
01:42
So the graph should look something like this.
01:51
So next the question asks, determine the critical points or the critical values.
01:57
So to do this, we have to take the first derivative.
02:06
So to differentiate this, we need to differentiate the power.
02:10
The derivative of 1 .5x is 1⁄2 times negative.
02:14
So negative 1 .5 .e to the 1 .5x power.
02:21
Next, we can set this equal to 0.
02:24
So let's ask yourselves, let's set the constant for a second and look at this part here.
02:30
When is this equal to 0? well, let's go ahead and look at this.
02:38
Now i know that this is a negative, so this is the negative counterpart to this, but let's just look at this for a second.
02:44
Does this ever cross the x -axis? no.
02:49
So if this function is never equal to zero, then the positive counterpart of this function is also not equal to zero anywhere.
02:59
So therefore, this function can never be zero.
03:04
So that means that there are no critical values.
03:10
Goodness, it's atrocious i.
03:14
No critical values.
03:21
Next, we can find the inflection points.
03:23
To do this, we can take the second derivative.
03:28
So let's differentiate again the derivative of this guy here, times by one -half again...