00:01
Hey guys, in this problem, we're going to be graphing and finding the critical values of the function, g of x equals e to the negative 2x.
00:12
So to start off, let's go ahead and set up our graph, including the negative x values.
00:25
So let's also set up our x, y, table, to get some values here.
00:31
So at negative 1, we have e to the negative 2 times negative 1, which is e to the 2.
00:36
You can plug that into your calculator.
00:40
Is about 7 .39.
00:46
At x equals 0, this whole term will become 1.
00:53
At x equals 1, we have e to the negative 2 times 1.
01:00
So e to the negative 2 is about 0 .135.
01:09
At x equals, oh, i wrote negative 1 by mistake.
01:14
At x equals 2, we have negative 2 times 2, so e to the negative 4.
01:21
Plug that in.
01:22
We have about 0 .018.
01:33
So let's go ahead and plot our points.
01:36
At negative 1 we have 1, 2, 3, 4, 5, 6, 7, 8.
01:43
So about right here.
01:48
At x equals 0, we have 1.
01:50
At x equals 1, we have 0 .135, about right here.
01:55
And it equals 2, we have 0 .018 very, very close to 0.
02:01
And the function will tend off to infinity and behave something like this.
02:14
So next, let's find our critical points.
02:17
So let's differentiate.
02:18
Finding the first derivative, we have negative 2 times e to the negative 2x.
02:26
That looks like a z to me, so i'm going to rewrite that negative 2.
02:33
Okay...