00:01
This problem is asking us to graph y equals log base 4 of 2x plus 3.
00:14
Okay, so i think it's kind of easiest if we just graph this equation right here.
00:21
Long equals, sorry, y equals log base 4 of 2x, and this plus 3 is a shift to the left of three points.
00:46
So first let's graph log base 4 of 2x and then we're going to shift it.
00:53
So in order to graph it, we need to know two things.
00:57
So we need to know that in this one, when x equals 0, when 2x equals 0, what happens? what happens when 2x equals 1? and then what happens when 2x equals our base? and then we're going to make a graph plotting my x and my y.
01:20
So when 2x equals 0, x equals 0.
01:26
So my 4 of y is going to equal 0.
01:32
So this can never happen, so that is where my asymptote is going to be.
01:39
So when x equals 0, that is my vertical asymptote.
01:44
Okay, now what's going to happen when 2x equals 1? well 2x equals 1, i divide up 2 on both sides and x equals 1 half.
01:53
So 4 to the power of y equals 1 because, well, let's do that, because we wanted to equal 2x, okay? but if x equals 1 half, we know that 4 to the y equals 1.
02:15
So that means that y has to equal 0.
02:19
So when x is 1⁄2, y is 0.
02:22
And then our last 2x equals 4, dividing off my 2 on both sides.
02:27
I know that x equals 2.
02:31
So what happens, 4 to the power of y equals 2x when x is 2, 4 to the power of 5, y equals 4.
02:42
So when x equals 2, y has to equal 1, because anything raised to 1 power is going to be itself.
02:49
So we're going to graph these few things...