00:01
Okay, so we want to force the kind again standard form.
00:07
So you factor out of four.
00:10
Let's see there'll be two here, sine of theta.
00:18
And you multiply 12 by 4.
00:22
And we have 1 minus 2, sine of theta.
00:27
4 divided by 4 is 3, sine of theta.
00:34
Okay, so we're on standard form now.
00:37
And we see that e is equal to 2.
00:43
This is greater than 1.
00:45
Therefore, we have a hyperbore.
00:53
We also see that we have a sign of theta in the denominator, a sine function.
01:02
And this implies that we are going to have a directrix, which is going to be y is equal to negative p.
01:08
We also see that in the numerator that e p is equal to three see you know e is two and therefore p is going to be three halves so this tells us that our directrix y is equal to negative p is negative three halves so a rough draft of the graph we will construct something like this.
01:43
So our directrix will be the line is negative, so horizontal line below the x -axis.
01:53
And then we have our focus is definitely going to be in the center.
01:59
And then since it's, let's see, we have negative signs that's going to open, or ellipse is going to open up, and then the other one is going to open back.
02:13
So we're interested in knowing this points here.
02:18
Let's say that was a.
02:19
Say this is b, this is c, this is d...