00:01
As i'm looking at this problem, what i would associate first is like log base b of m is whatever you're taking the log of, that value needs to be bigger than zero.
00:15
So as we're looking at this function, which is written as log base 5 of x plus 1, and you look at what's inside the parentheses, that must be at least a positive number.
00:30
So if you subtract 1 over, then that's going to be that values for x must be bigger than negative 1.
00:38
So if i go to my graph, what's really happening is i'm shifting my graph to the left one, and i have a vertical asymptote there.
00:50
And so when i strategically choose my values for x to make a table here, i would actually start at x equals 0, and then i would probably move to x equals 4, because then i can figure out that f of x.
01:05
Well, zero plus one is one, and i know that log base 5 of 1 is always equal to 0...