00:01
For this exercise, we have a quadratic that has been provided, and our job is to give a sketch for what its graph would look like.
00:08
We start by determining the vertex, which is a fast process, since this quadratic is already written in standard form.
00:16
So to get the x coordinate, we go here and take the opposite.
00:20
So we have positive a third, and to obtain the y coordinate, we directly copy this constant one -ninth.
00:27
So now we have that the vertex is at a third and a ninth.
00:31
So let's go a distance of a third in the x -axis direction.
00:35
I'll let these tick marks represent 1 3rd.
00:41
So we go 1 3rd in this direction, and then we have to go a distance of positive 1 3rd in the vertical direction.
00:50
So if this is 1 3rd, a 9th is a 3rd of a 3rd, which means this would be roughly 1 9th.
00:58
So this is where our vertex ends up at, and for the further analysis of this particular question, quadratic, notice that the leading coefficient is a positive one.
01:11
That means that our graph is going to be opening upwards.
01:14
But the next step to take is we're going to obtain a table of values, we'll call it x and y, and use this table to determine two more points.
01:26
Already we have the point one -third for x, one -ninth for y, so now our strategy is going to be pick a value here and here that's symmetrically the same distance away from one -third so that the values here and here will be identically equal.
01:44
One strategy here is if we go a distance of one away from the x value of one -third, we'll be adding one -third to obtain a value of four -thirds.
01:56
And if we go a distance of negative one -third away from one -thirds, we would be taking one -third minus one, which would become negative 2 thirds.
02:08
Let's evaluate say 4 thirds...