00:01
Here we see the function, f of x is equal to, well, x minus 1 times the quantity x squared minus 4.
00:08
That's all divided by x minus 2 times the quantity x squared plus 1.
00:13
Okay, that is graph here in desmos.
00:16
Now, to find our vertical asymptote, well, if that would occur, where the denominator is equal to zero.
00:26
Right? so, well, you can notice maybe a few things here.
00:31
You can first notice we have two things being multiplied together.
00:34
So this would be equal to zero when either factor would be equal to zero.
00:40
Well, x squared plus one, right? that is never equal to zero because x squared can never be negative and you're adding one.
00:48
So this factor is never equal to zero.
00:51
But x minus two, well, that's equal to zero where x equals two.
00:54
So we would think that we'd have a vertical asymptote at the line x equals two.
00:59
But wait a minute, notice that with x equals two, then in the numerator we have two factors, and this factor here, x squared minus four, well, if x is equal to two, we'd have two squared which is four, minus four, which is zero.
01:14
So if x is equal to two, right, the denominator is zero, because one factor is zero, but the numerator is also zero...