00:01
For the following problem, we are going to be looking to graph the set of points who's polar coordinate satisfy the equations and inequalities.
00:07
So if we have r equals 2, we know that's just going to be a radius of 2 no matter what the angle is.
00:12
So that's going to be a circle.
00:14
Then, however, if we're considering from 0 to 2, so that's going to be 0 is less than or equal to r, which is less than equal to 2, then what we end up seeing is that this will create a circle where all the points inside are filled.
00:29
Then if we have r is greater than or equal to one so we know that r is going to be greater than equal to one then what that's going to look like is a circle but everything outside of the circle is filled in then we'll have one is between one is less than equal to r which is less than equal to two so in that case we end up seeing that it's going to be a circle between radius one and radius two so if r equals one or equals two and it'll be the space filling in between creating some sort of a disk.
01:05
Then we'll also have different angle measurements.
01:07
So for example, if we're looking at the angle measurement, zero is less than or equal to theta, which is less than equal to pi over six, and we know that it can be any radius value, but we're going to have a sector from zero to pi over six, so zero to 30 degrees.
01:26
Then we have other possibilities such as theta equals two pi over three...