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Graph the solutions of each system.$$\left\{\begin{array}{l}{x+y>0} \\{y-x<-2}\end{array}\right.$$
$y-x<-2$
Algebra
Chapter 4
Systems of Linear Equations and Inequalities
Section 5
Solving Systems of Linear Inequalities
Equations and Inequalities
Systems of Equations and Inequalities
Missouri State University
Campbell University
McMaster University
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So here we will have the system of inequalities with X plus why this loss is greater than zero and why minus X is less than negative too. They were supposed to graph the solutions. But first we must find the equation of lines. And with this, we can simply have why? It s a lesson negative x, and our line is going to be. Why sequel to Negative X And here we're going to have. Why it iss less than X minus two. So our line is going to be why is equal to X minus two. And with this information, we can start crapping and our first line is going to be. Why is equal to negative sex and it will look like so. So that is our Why is equal to negative X and there Green Line is going to be Why is equal to X minus dio So this is negative too. My physical two x minus two No, to know which part of the graph is shaded. We can choose a point. Let's say we will have one one and plugging this end, we will have why it is greater than he'll have. One is greater than negative one which satisfy so be will shape the graph where that point ISS and the same as this one we can choose the point 00 and this will have us zero IHS less than zero minus two. This will have zero is less than negative to which doesn't satisfy, So we will shade the area that that point is not included. So in this part of the graph and we can see where these two overlaps and that is going to be our solution
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