00:01
We are going to plot the function absolute value of x over x in the interval negative 5 -5 and on the window negative 5 5 times negative 3 3 and we will explain why the derivative of f at 0 does not exist and if we try to find the numerical derivative at 0 of this function on a calculator we are going to discuss about obtaining any numerical value of that.
00:40
So in this case we we know that the function f given us the absolute value of x over x is not defined as zero because at zero we will have sorry you will have zero over zero which is not defined so for positive x we know this function is equal to 1 because let's see that for positive x, the absolute value of x is x x, we then divide x by itself equals 1 if x is positive and if x is negative, absolute value of x is negative x over x and that is negative 1.
01:42
So this function is equivalent to the function 1 for the positive and negative 1 for the negatives.
01:50
So the graph is more or less this graph here at the left where the blue line is a function and we know that this is infinite to the right to the left.
02:03
And at the point zero there is no definition of the function.
02:10
So this function is clearly not continuous at zero.
02:22
Simply because it's not there is no limit at that point and with that already we know that it's not continuous but it's not it also not defined at zero so in any way this function is discontinuous at zero and this implies that if derivative at zero cannot exist because if a function has a derivative at a point it get to be continuous at that point.
03:01
And in fact there is no reasonable way of defining a tangent line at zero.
03:08
Not possible to do that in this case...