00:01
So here we can say that the velocity here, velocity sub 1 minus the initial velocity, the velocity at any point in the graph minus the initial velocity, so the change in the velocity since the beginning.
00:17
This would be equaling to the area under the curve of an acceleration versus time graph.
00:34
And this is of course because the velocity is going to be the integral of the acceleration.
00:40
So for part a, we can see from figure 215a, the head begins to accelerate from rest.
00:48
And this would be velocity, the initial velocity of course, zero.
00:55
Time is equaling 110 milliseconds.
00:59
And this reaches a maximum value of 90 meters per se.
01:06
Squared at t sub 1 equaling 160 milliseconds.
01:16
So we can say that the area of this region would be equaling one half multiplied by 160, my apologies, 160 minus 110 times 10 to the negative third seconds multiplied by 90 meters per second squared and this is giving us 2 .25 meters per second and this is of course the value v sub 1 2 .25 meters per second at t sub 1 so this would be our answer for part a and for part b we know that to compute the speed of the torso at t sub 1 equaling 160 milliseconds we can divide the area into four regions so we can say from 0 seconds to 40 milliseconds, we can say region a has no area.
02:34
And then we can say from 40 milliseconds to 100 milliseconds, we can say that region b, the area of region b would be similar to the area of a triangle or one -half times the base times height.
02:49
So 1 .5 times 0 .06000 seconds multiplied by 50 .0 meters per second squared.
02:59
And this is giving us 1 .50 meters per second.
03:04
And then for area c, this would be 100 to 120 milliseconds.
03:11
And this has the shape of a rectangle.
03:14
So this would be 0 .0200 seconds...