00:01
So here, the key thing to remember here is that the position or the total displacement is simply the area beneath the curve of a velocity versus time graph.
00:16
So we can say that essentially the position is simply the integral of velocity.
00:22
Again, the integral being simply the area under the curve.
00:26
So we can say x sub 1 minus x not you can also say delta x however you would like to represent it this would simply be equal to the area between the velocity curve and the time axis from t sub 1 or other t sum t not or t initial to t sub 1 or again delta t so we can say that to compute the position and of the fist at t equals 50 milliseconds we just divide the area so for part a we can say that the area of part a would be simply equal to a triangle so one half times 0 .010 seconds multiplied by two meters per second this is equaling 0 .01 meter now for we can say the area sub b would be equal to here it would be a trapezoid so we can say 1 1 1�t times 0 .040 seconds.
01:49
This would be 10 milliseconds to 50 milliseconds.
01:53
So essentially 50 milliseconds minus 10 milliseconds.
01:57
This is equaling 0 .4 .040 seconds.
02:01
And then multiplied by 2 plus 4 units here of course meters per second.
02:05
This is equaling 0 .12 meters.
02:09
And then substituting these values into equation 230, we can have x sub 1 minus 0, equaling 0 plus 0 .01 plus 0 .12.
02:24
This is equaling 0 .13 meters or this is simply equaling x sub 1.
02:32
This would be our final answer for part a...