00:02
So again, we can use the factoring by substitution method to find our zeros for this polynomial.
00:09
So if i said u is equal to x cubed, what i get is is u squared minus 2 u plus 1.
00:18
And so we want two numbers that multiply to positive 1, but add up to negative 2.
00:23
And so this would be this would be minus 1.
00:26
So this would be u.
00:28
This would be u minus 1.
00:30
And then we'll have another u minus 1 here.
00:32
So this this we can say is just u minus 1 squared.
00:35
And so now what we have here is if i plug in you back in for x cubed, so let's do this, x cubed minus 1 squared.
00:48
And let's solve for, let's solve for x.
00:51
Well, this would be x is equal to 1...