00:01
We are first asked to find the energy of one photon of green light.
00:05
To find that energy of one photon of light, use the equation e equals hc over lambda, where h equals planks constant, or 6 .626 times 10 to the negative 34 joules times seconds, and c equals the speed of light, or 3 .0 times 10 to the 8 meters per second, and lambda stands for wavelength.
00:27
We are given planx constant 6 .626 times 10 to the negative 4 joules times seconds and the speed of light, 3 .8 times 10 to the 8 meters per second.
00:41
We are also given the wavelength of green light, which is 5 .0 times 10 to the second nanometers, or 5 .0 times 10 to the negative 7 meters.
00:52
We plug these given values into the equation.
00:55
To get energy equals 6 .626 times 10 to the negative 34 joules per second, multiplied by the speed of light 3 .0 times 10 to the 8 meters per second, all over the given wavelength, which is 5 .0 times 10 to the negative 7 meters.
01:12
When we solve this, we get energy equals 4 .0 times 10 to the negative 19.
01:18
To solve for units, we cancel out the meters in the denominator with the meters in the numerator...