00:01
In this question, we have to write first the combustion of octane, the formula is c8h18, to produce carbon dioxide and water.
00:21
Combustion is always done in the presence of oxygen, and the products are carbon dioxide and water.
00:30
Okay to balance this equation we have eight carbons we put an eight right here we have 18 hydrogens we put a nine here and then we're gonna have 16 plus 9 25 oxygen we put a 25 half here because this is a fraction and i don't know fractions i'm going to multiply this question by this equation by two and then we're going to get 2 c8h 18 plus 25 oxygens producing 16 molecules of carbon dioxide plus 18 molecules of water okay let's double check the balancing we have 18 carbons sorry 16 carbons 16 carbons 2 times 18 is 36 hydrogens 18 times 2 is 36 hydrogens then we have 50 oxygens from carbon dioxide we have 16 times 2 32 plus 18 is 50 oxygen so this equation is balanced.
02:09
With this equation, we need to calculate the mass of octane that is necessary, the mass in grams of obtain that is necessary to release five mole of carbon dioxide.
02:32
Because obtain and carbon dioxide are the substances involved in this particular question, i'm going to establish the mole ratio, between octane and carbon dioxide.
02:45
So we have two moles of octane reacting to produce 16 moles of carbon dioxide.
02:54
I'm going to write now this more ratio.
02:59
Two moles of octane react to produce 16 moles of carbon dioxide...