00:01
For this question with multiple parts, we'll start with the general expression for the ionization energy of any one electron species.
00:09
As mentioned in the chapter and in a previous problem, the energy is going to be equal to the constant 2 .18 times 10 to the negative 18, multiplied by the charge of the ion squared, the positive charge, divided by the energy level in which the electron is.
00:32
Found before removal.
00:35
It's then minus 1 over infinity but 1 over infinity is 0 so we don't need to include zero in our denominator.
00:44
We'll then multiply that by avogadro's number because this will be the energy for just one electron to determine the energy for the removal of a mole of electrons we multiply by avogadro's number.
00:59
So to determine the ionization energy for b4 plus it'll be 2 .18 times 10 to the negative 18 joules multiplied by boron has a charge on it in its nucleus of five so it'll be five squared don't let the four plus confuse you there's still one electron that's why the charge on the cat ion is four plus but the actual charge on the nucleus is five plus we divide that by the location of the last electron which which will be in the lowest energy state energy level 1 and multiply it by avogadro's number and we get 3 .28 times 10 to the 7 joules per mole.
01:44
Now to calculate the wavelength associated with the removal of an electron from helium plus in energy level 3, we use the same equation up here because it's helium, z is 2 and because we're removing it from energy level 3, then n is 3.
02:06
This will give us the energy.
02:08
We ultimately need the wavelength, but we need to get the energy first.
02:12
We get 9 .69 times 10 to negative 19 joules...