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Growing degree days The rate of development of many plant species depends on the temperature of the environment in such a way that maturity is reached only after a certain number of "degree-days." Suppose that temperature $T$ as a function of time $t$ is given by $$T(t)=15\left(1+\sin \frac{2 \pi t}{60}\right) \quad 0 \leqslant t \leqslant 60$$ where $t$ is measured in days. If maturity is reached on day$t=20,$ what is the number of degree-days required? $\left[$ Hint: What are the units for $\int_{0}^{20} T(t) d t ?$]$

515

Calculus 1 / AB

Calculus 2 / BC

Chapter 5

Integrals

Section 4

The Substitution Rule

Integration Techniques

Campbell University

Oregon State University

University of Nottingham

Boston College

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this question asked us to determine what is the number of degree days required. We know we've been given time. Twenties. We can make our bounds from 0 to 20 and then we know our function is 15 times one plus sign of to party over 60. Now, for this question, you can use a calculator for this one. Essentially, you can plug exactly this and your calculator. And don't forget the DT your calculator can't do d T. You could just replace t with XO everywhere where you have tea, just make it X said you'd have d X at the end. What we know is that we need to determine the number of degree days required. Therefore, what we know is that making our bounds what they are playing this in, you end up with 515 and the answer is degree days is our

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