Question
$g(x)=x^{3}-27 x$(a) Determine whether $g$ is even, odd, or neither.(b) There is a local minimum value of $-54$ at $3 .$ Determine the local maximum value.
Step 1
To do this, we replace $x$ with $-x$ in the function and simplify. So, $g(-x)=(-x)^{3}-27(-x)=-x^{3}+27x=-1(x^{3}-27x)=-g(x)$. Since $g(-x)=-g(x)$, we can conclude that the function $g(x)$ is odd. Show more…
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