Question
He period of revolution of planet $\mathrm{A}$ around the sun is 8 times that of $\mathrm{B}$. The distance of A from the sun is how many times greater than that of $\mathrm{B}$ from the sun.(A) 2(B) 3(C) 4(D) 5
Step 1
Mathematically, this can be written as: (T_A / T_B)^2 = (a_A / a_B)^3 where T_A and T_B are the periods of revolution of planets A and B, respectively, and a_A and a_B are their distances from the sun. Show more…
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He period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun. (A) 2 (B) 3 (C) 4 (D) 5
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