Heart muscle gets most of the ATP needed to power its continual contractions through oxidative phosphorylation. When oxidizing glucose to $\mathrm{CO}_{2}$, heart muscle consumes $\mathrm{O}_{2}$ at a rate of $10 \mu \mathrm{mol} / \mathrm{min}$ per $\mathrm{g}$ of tissue, in order to replace the ATP used in contraction and give a steady-state ATP concentration of $5 \mu \mathrm{mol} / \mathrm{g}$ of tissue. At this rate, how many seconds would it take the heart to consume an amount of ATP equal to its steady-state levels? (Complete oxidation of one molecule of glucose to $\mathrm{CO}_{2}$ yields 30 ATP, 26 of which are derived by oxidative phosphorylation using the 12 pairs of electrons captured in the electron carriers NADH and FADH $_{2}$.)