0:00
Hi there.
00:01
So for this problem, we're told that the average rate of solar radiation incident per unit area on the earth is equal to 0 .485 calories per centimeter square or a centimeter square per minute or also we can express this as 338 .138.
00:34
Watts per meter square.
00:40
So for part a of this problem, we need to explain the consistency of this number with the solar constant solar energy falling per unit time at normal incident on an unit area whose value is known and that is equal to 1 .94 calories per calories per centimeter square per minute, which in watts per square meter is equal to 1 ,353 watts per square meter.
01:23
So to calculate this, we know that the solar constant s is defined by the luminousal.
01:38
Of the sum divided by 4 times pi times its radius square, where art is the earth's distance, sun's distance, and l is the rate of energy output of the sun.
02:00
So let art be the capital art be the radius of the earth, and the rate p at which energy in plunges on the earth is defined as the sun divided by four times pi times the radius squared, the separation between the earth and the sun, and this times pi times the radius of the earth square.
02:32
So we can simplify that this is pi times the radius of the earth the square times s...