Heating solid sodium bicarbonate in a closed vessel establishes the following equilibrium:
$$
2 \mathrm{NaHCO}_{3}(s) \rightleftharpoons \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{CO}_{2}(g)
$$
What would happen to the equilibrium position if
(a) some of the $\mathrm{CO}_{2}$ were removed from the system; (b) some solid $\mathrm{Na}_{2} \mathrm{CO}_{3}$ were added to the system; (c) some of the solid $\mathrm{NaHCO}_{3}$ were removed from the system? The temperature remains constant.