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Height of a Ball If a ball is thrown directly upward with a velocity of $40 \mathrm{ft} / \mathrm{s}$, its height (in feet) after $t$ seconds is given by $y=40 t-16 t^{2}$. What is the maximum height attained by the ball?

$25 \mathrm{ft}$

Algebra

Chapter 3

Polynomial and Rational Functions

Section 1

Quadratic Functions and Models

Quadratic Functions

Polynomials

Rational Functions

Missouri State University

Campbell University

University of Michigan - Ann Arbor

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this question instructs us to find the maximum height obtained by the ball. What we know is that we have the function after of tea is 40 T minus 16 T square. This function has a maximum value because R is negative. Therefore, we can use the formula negative be over to eight solved. We know our B is 40 or a is negative. 16. This gives r T as five divided by four plug after five divided by four n Again, This is into the original function we're solving for our second co ordinate tweet. We end up with 25 because this is a word problem. Don't forget your unit. 25 feet is the

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