Height of a Projectile A projectile is launched from ground level with an initial velocity of $v_{0}$ feet per second. Neglecting air resistance, its height in feet $t$ seconds after launchis given by$$s=-16 t^{2}+v_{0} t$$
Find the time(s) that the projectile will (a) reach a height of 80 $\mathrm{ft}$. and (b) return to the ground for the given value of $v_{0}$. Round answers to the nearest hundredth if necessary.
$v_{0}=96$