00:01
In the given question we have been provided that for a protein at ph 2, the enthalpy change is given as delta h to be equal to 418 kilojoule per mole.
00:12
It is at temperature 298 kelvin.
00:16
And also we have been provided the entropy chain for this denaturation of protein that is equals to 1 .3 kilojoules kelvin inverse, mole inverse.
00:27
And they both are defined for the same temperature, that is 298 kelvin.
00:31
We have been asked in part a, what is the value of change in gibbs energy? if ph is 2 and the temperature is 305 kelvin, and we have been 310 kelvin, and we have been provided between 298 to 310 kelvin, delta h0 and delta s not are constant.
00:55
There will be correction.
00:56
It is mentioned 303 but the temperature is 310 kelvin.
01:00
Okay, so for this temperature range, delta s not and delta s not are constant.
01:04
So how we can find the delta g not, we will first calculate delta g not at 298 kelvin.
01:12
Okay, we have been asked the value of delta g for that we will find the delta g not at 298 kelvin.
01:20
Okay, and that will be equal to delta h at this temperature, minus temperature multiplied by change in entropy.
01:30
So our delta h at this temperature is 418 kilojoules minus the temperature.
01:37
Our temperature at given is 298 and delta s is 1 .3 kilojoule kelvin inverse.
01:45
Now on doing the calculation, we will get the delta g at 298 kelvin to be equal to 30 .41 kilojoule per more.
01:56
Okay, this is our delta g at 298 kelvin.
02:00
Now to find the delta g not at delta g sorry, delta g at 310 kelvin, we can use the expression that delta g at 310 kelvin will be equals to the temperature that is 310 into delta g at a different temperature.
02:17
So we know the delta g at 298 divided by the temperature which is 298 plus delta h at this temperature...