00:01
Okay, what we're going to do is we're going to talk about horizontal motion.
00:04
And so we're given a position function as x of t is equal to a, e to the kt, plus b, e to the negative kt.
00:11
Where a, b, and k are just positive constants.
00:15
And the first thing we want to do is we want to determine the time when the position of the particle or whatever is moving is closest.
00:33
To the origin.
00:36
Okay, so if we think about this, we want to minimize that position.
00:42
We want the minimal position.
00:43
And so we have to think, okay, maximums and minimums occur at our critical numbers, where our first derivative actually equals zero.
00:54
And so that's, we're going to take the first derivative.
00:58
And so this would be a, k, e to the kt, minus bk, e to the negative kt.
01:07
Okay, and so we're going to go ahead and put this over a common denominator.
01:12
So we have ak, oops, e to the 2kt minus bk all over e to the kt.
01:28
Okay, and so we're going to set this equal to zero because we're solving for the critical numbers where that derivative equals zero.
01:36
And of course, it's going to be where your numerator equals zero.
01:45
And we're going to solve for t.
01:47
And so when we do that, we get e to the 2kt is equal to b over a.
01:55
And so, of course, we're going to take the natural log of both sides.
01:59
And so we get t is equal to 1 over 2k natural log of b over.
02:08
So there is our critical number...