Then, we react it with excess of methylmagnesium bromide (CH3MgBr) in ether to form a tertiary alcohol. The reaction is as follows:
\[
\begin{align*}
\text{CH3C6H5} + \text{Br2} &\xrightarrow{\text{hv}} \text{C6H5CH2Br} \\
\text{C6H5CH2Br} + 2\text{CH3MgBr}
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