Question
How can you explain the fact that trans-1-bromo-2-methylcyclohexane yields the non-Zaitsev elimination product 3 -methylcyclohexene on treatment with base? (EQUATION CAN'T COPY)
Step 1
In this conformation, the bromine atom is in the axial position at carbon 1, the methyl group is in the axial position at carbon 2, and a hydrogen atom is in the equatorial position at carbon 2. \[ \begin{array}{c} \text { Show more…
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How can you explain the fact that trans-1-bromo-2-methylcyclohexane yields the non-Zaitsev elimination product 3-methylcyclohexene on treatment with base?
How can you explain the fact that trans-1-bromo-2-methylcyclohexane yields the non-Zaitsev elimination product 3 -methylcyclohexene on treatment with base? trans-1-Bromo-2-methylcyclohexane $\quad$ 3-Methylcyclohexene
How can you explain the fact that trans- - -bromo-2-methylcyclohexane yieids the non-Zaitsev elimination product 3-methylcyclohexene on treatment with base?
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