Question
How does each of the following changes affect the rate of an $E2$ reaction?a. tripling [RX] b.halving [B:] c. changing the solvent from $CH_3OH$ to $DMSO$ d. changing the leaving group from $I^-$ to $Br^-$ e. changing the base from $^-OH$ to $H_2O$f. changing the alkyl halide from $CH_3CH_2Br$ to $(CH_3)_2CHBr$
Step 1
Therefore, if we triple the concentration of the alkyl halide [RX], the rate of the reaction will also triple. Mathematically, this can be represented as: \[Rate \propto [RX]\] So, if [RX] is tripled, then the rate will also triple. Show more…
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How does each of the following changes affect the rate of an E2 reaction? a. tripling [RX] b. halving [B:] c. changing the solvent from $\mathrm{CH}_{3} \mathrm{OH}$ to DMSO d. changing the leaving group from $I^{-}$ to $B r^{-}$ e. changing the base from ${ }^{-} \mathrm{OH}$ to $\mathrm{H}_{2} \mathrm{O}$ f. changing the alkyl halide from $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br}$ to $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHBr}$
How does each of the following changes affect the rate of an E1 reaction? a. doubling [RX] b. doubling [B:] c. changing the halide from $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}$ to $\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br}$ d. changing the leaving group from $\mathrm{Cl}^{-}$ to $\mathrm{Br}^{-}$ e. changing the solvent from DMSO to $\mathrm{CH}_{3} \mathrm{OH}$
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