How does the $\mathrm{S}_{\mathrm{N}} 1$ mechanism for the hydrolysis of 2-bromo-3-methylbutane, a $2^{\circ}$ alkyl bromide, to give exclusively the $3^{\circ}$ alcohol 2-methyl-2-butanol, establish a carbocation intermediate?
The initial slow step is dissociation to the $2^{\circ}$ 1,2-dimethylpropyl cation. A hydride shift yields the more stable $3^{\circ}$ carbocation, which reacts with $\mathrm{H}_2 \mathrm{O}$ to form the $3^{\circ}$ alcohol.